Difference between revisions of "User talk:DerFlob"
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I don't get it, why is 1*π half of pi? Shouldn't it be 1*π=π? For me, π/2 is still half of pi, i.e. somewhat around 1.505 Or did you mean to make a connection to the circular shape of the pie so that the remaining pie would account for (2π[radius of Johanna's pie])/2? Please enlight me! ;) -[[User:The T-Man|The T-Man]] 08:43, 16 March 2012 (EDT) | I don't get it, why is 1*π half of pi? Shouldn't it be 1*π=π? For me, π/2 is still half of pi, i.e. somewhat around 1.505 Or did you mean to make a connection to the circular shape of the pie so that the remaining pie would account for (2π[radius of Johanna's pie])/2? Please enlight me! ;) -[[User:The T-Man|The T-Man]] 08:43, 16 March 2012 (EDT) | ||
| + | :It's your second guess. Half a circle (i.e. the pie) is one pi. Maybe it would be better if we write "One more π remaining" as a caption? -[[User:DerFlob|DerFlob]] 13:34, 16 March 2012 (EDT) | ||
Revision as of 17:34, 16 March 2012
- I just wrote the report and added the pics for 2010-06-23 48 11, hope we can work on our epic achievement collection hash soon ;D The T-Man 11:07, 3 February 2011 (EST)
Sunday 27 Feb Geohash - just a short walk south from Rohrbach, on RE 59096. Interested? What time? I'm in Munich for a conference until Monday. --Thomcat 02:23, 26 February 2011 (EST)
2011-04-30 47 13 - de-virginizing Salzburg
I plan to go there, dawidi will probably join. It's not only a bit crazy but that's what we are geohashers for. If you would like to join, drop us a note ;) --Ekorren 11:29, 29 April 2011 (EDT)
- Sorry, just found out that Salzburg is not virgin - it's just that the one who did an expedition there didn't link it anywhere. Still considering to go there, but under these circumstances there might be other options as well. --Ekorren 11:58, 29 April 2011 (EDT)
Pi
I don't get it, why is 1*π half of pi? Shouldn't it be 1*π=π? For me, π/2 is still half of pi, i.e. somewhat around 1.505 Or did you mean to make a connection to the circular shape of the pie so that the remaining pie would account for (2π[radius of Johanna's pie])/2? Please enlight me! ;) -The T-Man 08:43, 16 March 2012 (EDT)
- It's your second guess. Half a circle (i.e. the pie) is one pi. Maybe it would be better if we write "One more π remaining" as a caption? -DerFlob 13:34, 16 March 2012 (EDT)
